Uhla lwemibhalo ye-athikili
Ngingavula futhi ngiqondise kanjani efasiteleni elisha lezixhumanisi zabaphawuli be -WordPress?
Beka amazwana izixhumanisi zangaphandle zidlulisele ngokuzenzakalelayo kumakhodi ezixhumanisi zangaphakathi
Uma ungafuni ukuthi abanye abantu bagcwalise ngamabomu i-URL yewebhusayithi evinjiwe kusixhumanisi sobeka amazwana, ngoba isixhumanisi esinjalo sisengozini yokuvinjwa.
Ngakho-ke, lesi sihloko siyaqhubeka nokwabelana: Umbhali we-WordPress isixhumanisi sangaphandle ukuguqulwa okuzenzakalelayo kube ikhodi yesixhumanisi sangaphakathi.
Isinyathelo 1: Guqula ngokuzenzakalelayo isixhumanisi sangaphandle se-athikili sibe ikhodi yangaphakathi yesixhumanisi
Sicela ugcwalise ikhodi kulesi sifundo, " Ungaziguqula kanjani izixhumanisi zangemuva zibe izixhumanisi zangaphakathi ku-WordPress? Ikhodi yokuguqula ngokuzenzakalelayo izixhumanisi zangemuva zesihloko zibe izixhumanisi zangaphakathi, " ngaphambi kokuqhubeka nalesi sifundo.
Isinyathelo sesi-2: Engeza Isixhumanisi Sokuphawula Ikhodi Yeqa
Engeza ikhodi elandelayo kufayela le-function.php letimu yakho ye-WordPress.
2-kuya-1 ikhodi:
- 1) [Kunconyiwe] Isixhumanisi sobeka amazwana siyeqa futhi sivule ikhodi efasiteleni elisha (ukubethela kwe-base64)
- 2) Isixhumanisi sobeka amazwana siyeqa futhi sivule ikhodi efasiteleni elisha (akukho ukubethela)
1) [Kunconyiwe] Isixhumanisi sombeki mazwana siyeqa futhi iwindi elisha livula ikhodi (ukubethela kwe-base64):
// 评论者链接跳转并新窗口打开(base64加密)
function commentauthor($comment_ID = 0) {
$url = get_comment_author_url( $comment_ID );
$author = get_comment_author( $comment_ID );
if ( empty( $url ) || 'http://' == $url )
echo $author;
else
echo "<a href='go.html?url=".base64_encode($url)."' rel='external nofollow' target='_blank' class='url'>$author</a>";
}2) Isixhumanisi sobeka amazwana siyeqa futhi sivule ikhodi efasiteleni elisha (akukho ukubethela):
// 评论者链接跳转并新窗口打开(无加密)
function commentauthor($comment_ID = 0) {
$url = get_comment_author_url( $comment_ID );
$author = get_comment_author( $comment_ID );
if ( empty( $url ) || 'http://' == $url )
echo $author;
else
echo "<a href='go.html?url=$url' rel='external nofollow' target='_blank' class='url'>$author</a>";Uma ufuna isixhumanisi sokugxuma sombuyekezi sikwazi ukubonisa i-URL, ungakhetha ukuthi ayikho ikhodi yokubhala.
Ngethemba ukuthi isihloko esithi "Ungazivula kanjani futhi uqondise kabusha izixhumanisi zabaphawuli be-WordPress efasiteleni elisha? Ikhodi yokuguqula ngokuzenzakalelayo izixhumanisi zamazwana zangaphandle zibe izixhumanisi zangaphakathi" esabiwe kubhulogi likaChen Weiliang ( https://www.chenweiliang.com/ ) izokusiza.
Zizwe ukhululekile ukwabelana ngalesi sixhumanisi sendatshana: https://www.chenweiliang.com/cwl-631.html
