Uhla lwemibhalo ye-athikili
WordPressIsixhumanisi sobeka amazwana sivuleka kanjani futhi sigxume efasiteleni elisha?
Beka amazwana izixhumanisi zangaphandle zidlulisele ngokuzenzakalelayo kumakhodi ezixhumanisi zangaphakathi
Uma ungafuni ukuthi abanye abantu bagcwalise ngamabomu i-URL yewebhusayithi evinjiwe kusixhumanisi sobeka amazwana, ngoba isixhumanisi esinjalo sisengozini yokuvinjwa.
Ngakho-ke, lesi sihloko siyaqhubeka nokwabelana:Izixhumanisi zangaphandle zabahlaziyi be-WordPress ziguqulwa ngokuzenzakalela zibe amakhodi esixhumanisi sangaphakathi
Isinyathelo 1: Guqula ngokuzenzakalelayo isixhumanisi sangaphandle se-athikili sibe ikhodi yangaphakathi yesixhumanisi
Sicela uqedele lesi sifundo kuqalaI-WordPress iziguqula kanjani izixhumanisi zangaphandle zibe izixhumanisi zangaphakathi?Isixhumanisi sangaphandle se-athikili siguqulwa ngokuzenzakalela sibe ikhodi yesixhumanisi yangaphakathi", ngaphambi kokuqhubeka nokusebenzisa lesi sifundo.
Isinyathelo sesi-2: Engeza Isixhumanisi Sokuphawula Ikhodi Yeqa
Engeza ikhodi elandelayo kufayela le-function.php letimu yakho ye-WordPress.
2-kuya-1 ikhodi:
- 1) [Kunconyiwe] Isixhumanisi sobeka amazwana siyeqa futhi sivule ikhodi efasiteleni elisha (ukubethela kwe-base64)
- 2) Isixhumanisi sobeka amazwana siyeqa futhi sivule ikhodi efasiteleni elisha (akukho ukubethela)
1) [Kunconyiwe] Isixhumanisi sombeki mazwana siyeqa futhi iwindi elisha livula ikhodi (ukubethela kwe-base64):
// 评论者链接跳转并新窗口打开(base64加密) function commentauthor($comment_ID = 0) { $url = get_comment_author_url( $comment_ID ); $author = get_comment_author( $comment_ID ); if ( empty( $url ) || 'http://' == $url ) echo $author; else echo "<a href='go.html?url=".base64_encode($url)."' rel='external nofollow' target='_blank' class='url'>$author</a>"; }
2) Isixhumanisi sobeka amazwana siyeqa futhi sivule ikhodi efasiteleni elisha (akukho ukubethela):
// 评论者链接跳转并新窗口打开(无加密) function commentauthor($comment_ID = 0) { $url = get_comment_author_url( $comment_ID ); $author = get_comment_author( $comment_ID ); if ( empty( $url ) || 'http://' == $url ) echo $author; else echo "<a href='go.html?url=$url' rel='external nofollow' target='_blank' class='url'>$author</a>";
Uma ufuna isixhumanisi sokugxuma sombuyekezi sikwazi ukubonisa i-URL, ungakhetha ukuthi ayikho ikhodi yokubhala.
I-Hope Chen Weiliang Blog ( https://www.chenweiliang.com/ ) kwabiwe "Isixhumanisi somhlaziyi we-WordPress sivuleka kanjani futhi sigxume efasiteleni elisha?Phawula ngokudluliswa okuzenzakalelayo kweketango langaphandle kukhodi yeketango langaphakathi", okuwusizo kuwe.
Siyakwamukela ukwabelana ngesixhumanisi salesi sihloko:https://www.chenweiliang.com/cwl-631.html
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